-6+x^4-x^2 The expression represents a (options: Linear, Quintic, Quadratic, Cubic, and Quartic) polynomial with ( ) terms. The constant term is ( ), the leading term is ( ), and the leading co-efficient is ( )

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

what am i trying to find out. you didn't put up the whole question.

step-by-step explanation: