What is the length of JK¯¯¯¯¯, to the nearest tenth of a millimeter? 4.5 mm 5.6 mm 8.3 mm 19.9 mm A horizontally-aligned scalene triangle J K L. Side J L is labeled as 3 millimeters. Side L K is labeled as 5 millimeters. Angle L is labeled as 62 degrees.

5 = side a

3 = side c

angle B = 62 degrees

JK is side b

Use the Law of Cosines to find the length of side b.

b^2 = a^2 + c^2 − 2ac cos(B)

b^2 = (5^2 + 3^2) − ( 2 x 5 x 3) cos(62°)

b^2 = (25 + 9) − 30 x 0.469

b^2 = 34 - 30 x 0.469

b^2 = 34 - 14.084

b^2 = 19.916

b = √19.916

b = 4.463

Rounded to the nearest tenth is 4.5 mm.

Hope this helps!

Step-by-step explanation:

4.5 mm

Step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47