"Find the missing side Lengths. Leave your awnser as radicals in simple form" Someone please help me. Please show me how you did it.

Step-by-step explanation:

5) x = 6sin45 = 6(√2)/2 = 3√2

   y = 6cos45 = 6(√2)/2 = 3√2

6) x = 2√6sin45 = 2√6(√2)/2 = 2√3

   y = 2√6cos45 = 2√6(√2)/2 = 2√3

7) x = 16sin60 = 16(√3)/2 = 8√

   y = 16cos60 = 16(½) = 8

8) u = 2/sin30 = 2 / ½ = 4

   v = 2/tan30 = 2/(1 /√3) = 2√3

Please select as brainliest if it fits.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

i think the answer is b.

step-by-step explanation:

not 100% sure though.