Help!!
 Show that 1 + tan2(x) = sec2(x)​

tan2(x) + 1 = sin2(x)/cos2(x) + 1 = [sin2(x) + cos2(x)]/cos2(x) = 1/cos2(x) = (1/cos(x))2 = sec2(x). Thus tan2(x) + 1 = sec2(x).

tan2(x) + 1 = sin2(x)/cos2(x) + 1 = [sin2(x) + cos2(x)]/cos2(x) = 1/cos2(x) = (1/cos(x))2 = sec2(x). Thus tan2(x) + 1 = sec2(x).

Step-by-step explanation:

Not an identity

Step-by-step explanation:

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

step-by-step explanation:

when the line is solid:

when the line is dashed:

this > inequality sign means:

this < inequality sign means:

this > inequality sign means:

this < inequality sign means:

about the problem:

srry i'm not done ! i'll