The speed of a boat in still water is 10 km/hr. The boat travels 24 km upstream, turns around and comes back the same route. The entire trip takes 5 hours, What is the
speed of the current?

rate of the current = 2 km/hr

Step-by-step explanation:

d = rt

Let c = rate of the current

Rate of boat downstream = 10 + c

Time going downstream = 24/(10 + c)

Rate of boat upstream = 10 - c

Time going upstream = 24/(10 - c)

Since the total time is 5 hr, then

24/(10 + c) + 24/(10 - c) = 5

24(10 - c) + 24(10 + c) = 5(10 + c)(10 - c)

240 - 24c + 240 + 24c = 500 - 5c^2

480 = 500 - 5c^2

5c^2 = 20

c^2 = 4

c = 2  or  -2

Since a rate cannot be negative, the rate of the current = 2 km/hr

the factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. hope this ! mark brainliest! you v much! : )

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step-by-step explanation: