A parabola has its minimum point at (3,-5) and the y coordinate of the y-intercept is -2. What is the equation of the parabola?

y = x² - 2x - 2

Step-by-step explanation:

x-coordinate of the vertex of a parabola is ( )

y = f(x) = ax² + bx + c

(x, y) ∈ f(x)

~~~~~~~~~

{ (0, - 2), (3, - 5) } ⊂ { (x, y): y = ax² + bx + c }

a(0)² + b(0) + c = - 2 ⇒ c = - 2

a(3)² + b(3) + ( - 2) = - 5  

9a + 3b - 2 = - 5 ⇒ 3a + b = - 1

= 3 ⇒ b = - 6a

3a + ( - 6a) = - 1

a =

b = - 2

y = x² - 2x - 2

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: