Find equation of the line that contains the point (4,-2) and is perpendicular to the line y= _2x+8

9514 1404 393

  y = 1/2x -4

Step-by-step explanation:

We presume the given line is ...

  y = -2x +8

This is in slope-intercept form, which allows us to determine easily that the slope of this line is -2.

A perpendicular line will have a slope that is the opposite reciprocal of -2:

  m = -1/(-2) = 1/2

The y-intercept of the desired line can be found from the point (x, y) = (4, -2) using the equation ...

  b = y - mx

  b = -2 -(1/2)(4) = -4

Now, we know the slope and y-intercept of the desired perpendicular line through (4, -2), so we can write its equation as ...

  y = 1/2x -4

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Additional comment

"Slope-intercept form" is ...

  y = mx + b . . . . . . where m is the slope and b is the y-intercept

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.