Cheryl painted her living room walls with two different colors. She painted part of the room yellow and another part green. If the surface area of the walls in her room is 720 ft2 and she painted 288 ft2 yellow, what percent of the room did she paint green?

Total percent of the room did she paint green = 60%

Step-by-step explanation:

Given - Cheryl painted her living room walls with two different colors. She painted part of the room yellow and another part green. If the surface area of the walls in her room is 720 ft² and she painted 288 ft² yellow.

To find - What percent of the room did she paint green ?

Proof -

Given that,

The surface area of the walls in her room = 720 ft²

Total area painted in yellow color = 288 ft²

So,

Total area painted in green color would be = 720 - 288 = 432 ft²

Now,

Let the total percent green color painted = x

So,

720 × x% = 432

⇒

⇒ x = = 60

∴ we get

Total percent of the room did she paint green = 60%

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680