An observer (O) is located 900 feet from a building (B). The observer notices a helicopter (H) flying at a 49° angle of elevation from his line of sight. How high is the helicopter flying over the building? You must show all work and calculations to receive full credit. (10 points) A right triangle is shown with one leg measuring 900 and another leg measuring h with an angle across from it measuring 49 degr

1035.33 feet

Step-by-step explanation:

Use the tan function, since we are given an angle and the measures of two legs of the triangle.

tan =

tan 49° =

Multiply each side by 900

900(tan 49°) = h

1035.33 = h

So, the helicopter is flying 1035.33 feet over the building

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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