N artist makes three types of ceramic statues (large, medium, and small) at a monthly cost of $760 for 210 statues. The manufacturing costs for the three types are $5, $4, and $3. If the statues sell for $26, $18, and $15, respectively, how many of each type should be made to produce $3,640 in monthly revenue?

20, 90 and 100

Step-by-step explanation:

Total number of statues = 210

Assuming that a large statue = x, medium statue = y and a small statue = z

Then, x + y + z = 210i

Also, we're told that the monthly cost is $760, so

5x + 4y + 3z = 760ii

Cost of selling is $3640, so then

26x + 18y + 15z = 3640iii

Solving i and ii simultaneously, we have

5x + 5y + 5z = 1050

5x + 4y + 3z = 760

Subtracting, we have

y + 2z = 290iv

Again, solving ii and iii simultaneously, we have

130x + 104y + 78z = 19760

130x + 90y + 75z = 18200

On subtracting, we have

14y + 3z = 1560v

And finally, solving iv and v simultaneously, we also have

14y + 28z = 4060

14y + 3z = 1560

On subtracting,

25z = 2500

z = 2500 / 25

z = 100

Substituting for z = 100 in iv, we have

y + 2(100) = 290

y + 200 = 290

y = 290 - 200

y = 90

Substituting for y = 90, and z = 100 in i

x + 90 + 100 = 210

x + 190 = 210

x = 210 - 190

x = 20

Therefore, large statues has to be 20, medium statues has to be 90, and small statues has to be 100

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation: