1. What is the equation of a parabola that has a vertex at (-2, 4) and goes through the point (0,8)?

y - k = (x + 2)^2

Step-by-step explanation:

The vertex equation of a vertical parabola is

y - k = a(x - h)^2, where (h, k) is the vertex.

We are given h = -2, k = 4, x = 0 and y = 8 and need to find the value of a.

8 - 4 = a(0 + 2)^2, or

4 = 4a, so a must be 1.

Then the desired equation is:

y - k = (x + 2)^2

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b