Using diagonals from a common vertex, how many triangles could be formed from the polygon pictured below?

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225

hope this is what you were asking for!

step-by-step explanation:

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen