Scott paid 10.47 for a 6.08 - kg bag of dog food. A few weeks later, he paid 13.88 for a7.48 -kg bag at a different store. Find the unit price for each bag. Then state which bag is the better buy based on the unit price. Round your answers to the nearest cent.

Scott paid $ 1.72 per kilo for the first bag, and $ 1.85 per kilo for the second bag, with which the best buy is the first bag.

Step-by-step explanation:

Since Scott paid 10.47 for a 6.08-kg bag of dog food, while a few weeks later, he paid 13.88 for a7.48-kg bag at a different store, to find the unit price for each bag, and then state which bag is the better buy based on the unit price, the following calculation must be performed:

10.47 / 6.08 = X

1.72 = X

13.88 / 7.48 = X

1.85 = X

Thus, Scott paid $ 1.72 per kilo for the first bag, and $ 1.85 per kilo for the second bag, with which the best buy is the first bag.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)