The following set of data represents the age in years of newly married ladies in Desai. 15,25,17,20,22,24,19,16./ This data was collected after Deborah made an allegation that ladies in Desai get married at an age other than 18 years as is required by law. Does this data provide enough evidence at 5% level of significance to believe that the mean ages of ladies getting married in Desai is actually different from 18 years as claimed by Deborah?​

There is no significant evidence to conclude that the mean ages of ladies getting married in Desai is different from 18.

Step-by-step explanation:

Given the data:

15,25,17,20,22,24,19,16

Using calculator :

Mean value, xbar = 19.75

Standard deviation, s = 3.69

Samoke size, n

H0 : μ = 18

H1 : μ > 18

The test statistic :

Tstatistic = (xbar - μ) ÷ (s / sqrt(n))

Test statistic = (19.75 - 18) ÷ 3.69/ sqrt(8))

Test statistic = 1.75 ÷ 1.3046

Test statistic = 1.34

The Pvalue from test statistic ; df = n - 1 = 8 - 1 = 7

Pvalue = 0.111054

Decision :

If Pvalue < α ; reject H0

0.111053 > 0.05 ` Hence, we fail to reject H0

We can conclude that, There is no significant evidence to conclude that the mean ages of ladies getting married in Desai is different from 18.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet