100 POINTS!! PLEASE HELP IM REALLY CONFUSED

what grade is this i will help u what grade is sir.

1:

<A=½(arcJL)=½(70+120)=35+60=95°

[inscribed angle is half of central angle]

2:

<W=½arcVX=½(130)=65°

[inscribed angle is half of central angle]

3.

<E=½(arcDC)=½(90)=45°

[inscribed angle is half of central angle]

4.

<R=½(arcXZ)=½(110+62)=86°

[inscribed angle is half of central angle]

5.

<B=½(arc DC)=½×104°=52°

[inscribed angle is half of central angle]

6.

<K=90°

[inscribed angle in a diameter is complementary]

<K+<J+<L=180°(sum of interior angle of a triangle]

<L=180°-90°-53°=37°

again

arc JK=2×<L=2×37=74°

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.