If a ball is dropped on the ground from a height of h meters, then the ball reaches the ground with the velocity 4.43h m/sec. Find the velocity with which a ball reaches the ground when it is dropped from a height of 32 m.

v = 141.76 m/s

Step-by-step explanation:

Given that,

The ball reaches the ground with a velocity of 4.43h m/sec.

We need to find the velocity of the ball at a height of 32 m.

Since, v = 4.43h

Put h = 32 m in the above expression.

v = 4.43(32)

v = 141.76 m/s

So, the velocity of the ball is equal to 141.76 m/s.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.