Solve sec^2(x) tan^2(x)+ sec(x) over 0 to 2pi A pi/2 (less than) x (less than) 3pi/2
B 0 (less than) x (less than) pi
C 0 (less than) x (less than) pi and 3pi/2 (less than or equal to) x (less than or equal to) 2pi
D 0 (less than or equal to) x (less than) pi/2 and 3pi/2 (less than) x (less than or equal to) 2pi

okay wait before i answer, is this for your points on a graph?

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3