Pls even multiple methoddd i'll give brainliest to the one w procedure

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we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

no because mercury has a density of 13.6 grams per centimeter squared while gold has 19.32 grams centimeter squared

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answer: answer is b.

[m < b = 120º]

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d is the only accurate one

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