In an effort to determine the most effective way to teach safety principles to a group of employees, four different methods were tried. Some employees were given programmed instruction booklets and worked through the course at their own pace. Other employees attended lectures. A third group watched a television presentation, and a fourth group we divided into small discussion groups. A high of 10 was possible. A sample of 5 tests were selected from each group. The results were: Sample Programmed Instruction Lecture TV Group Discussion 1 6 8 7 8 2 7 5 9 5 3 6 8 6 6 4 5 6 8 6 5 6 8 5 5 At the 0.01 level, what is the critical value

critical value = 5.29

Step-by-step explanation:

Given that they are divided into 4 groups and a sample of 5 test was selected

N = 5 * 4 = 20

k = 4

∝ = 0.01

Df for numerator ( SS group )= k - 1 = 3

Df for denominator ( SSE group )  = N - k = 20 - 4 = 16

DF ( degree of freedom )

Next we will use the F table to determine the critical value

Critical value =   = 5.29

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4