Here are summary statistics for randomly selected weights of newborn​ girls: n​=250, x_=32.9 ​hg, s= 6.9 hg. Construct a confidence interval estimate of the mean. Use a ​95% confidence level. Are these results very different from the confidence interval 31.9 hg < μ < 34.5 hg with only 19 sample​ values, x_=33.2 ​hg, and s=2.6hg? What is the confidence interval for the population mean ​μ?

a)  ( 31.92 < μ < 33.88 )  

The confidence interval is not very different from the confidence interval given in the question

b) ( 31.74 ,  34.66 )

Step-by-step explanation:

n = 250

x ( mean ) = 32.9

std = 6.9

95% confidence interval

df = n - 1 = 250 - 1 = 249

a) construct confidence interval estimate

calculate for the margin of error

= ( using excel function:  T.INV.2T(0.025,249) )

= 2.255 ( 6.9 / 15.81 )

= 0.98

Hence the confidence interval for the population

= ( x - 0.98 < μ < x + 0.98 )

= ( 31.92 < μ < 33.88 )  

The confidence interval is not very different from the confidence interval given in the question

b) when n = 19

x = 33.2 and std = 2.6

margin of error = = 2.45 * ( 2.6 / 4.36 )  = 1.46

confidence interval

= ( 33.2 - 1.46 , 33.2 + 1.46 )

= ( 31.74 ,  34.66 )

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: