Consider the equation of parabola y = 5x - 30x + 45. Its vertex is located at
( , )

(3, 0 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c (a ≠ 0 )

Then the x- coordinate of the vertex is

= -

y = 5x² - 30x + 45 ← is in standard form

with a = 5, b = - 30 , then

= - = 3

Substitute x = 3 into the function for corresponding value of y

y = 5(3)² - 30(3) + 45 = 45 - 90 + 45 = 0

vertex = (3, 0 )

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.