The functions f(x) = 2x2 + 2 and g(x) = 2x+1 + 2 are graphed on the coordinate plane as shown. 32
24
16
8+000
0
1
2
For what values of x is g(x) > f(x)?
O A 0 < x < 2 and x > 4
OB. 2 C. X > 4
OD. X > 2

i had got the second answer

Step-by-step explanation:

Step-by-step explanation:

Given the functions f(x) = 2x^2 + 2 and g(x) = 2^x+1 + 2

If g(x) > f(x)

2^(x+1) + 2  > 2x^2 + 2

2^x*2 + 2 >2x^2 + 2

2^x*2 >2x^2

2^x > x^2

2^x - x^2 > 0

0 < x < 2 and x > 4

Step-by-step explanation:

..

faster, im not sure why but i know it is faster

at least two

step-by-step explanation: