Find the value of the wrapping function W (t) = (x, y) for the real number t=8pie/3. Recall that this is the same as finding the point (x, y) on the unit circle corresponding to the
standard position angle t =
8pie/3

the answer is a

step-by-step explanation:

because your just changing the position of where the shape is

5x+10 is the correct one

hope this

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15