Can someone please help me with this math problem? Please. Simplify the expression:(2x-3y)^2/(3y-2x)^2 Ava simplified the expression and said that the value is -1. (2x-3y)^2/(3y-2x)^2 (2x-3y)^2/-(2x-3y)^2 and then she has both of them crossed out (2x-3y)^2/-1(2x=3y)^2 =-1 Is Ava's solution correct? If not, find and explain her mistake. Give the correct solution.

Ava is incorrect

Step-by-step explanation:

Given

Required

Determine if Ava is correct or not

Ava's solution is incorrect and the proof is as follows;

Apply the following law of indices;

Rewrite the numerator

Cross out the common factor of the numerator and denominator

Hence, the solution is 1; not -1

Her mistake is that, she did not apply the square on -1, after she factorize the denominator

i need points

step-by-step explanation:

sorry bubs