1.evaluate
8
e -(n-5)
n=2
sigma notation

The sigma means that you add up all the values you get after you plug in the designated range of n. 

so, what that means in simplest terms: 

plug in the value for n on the bottom first, which is 2. then plug in everything up to the number on top of the sigma 

so you'd plug in, 2 for n, then, 3, then 4, then 5, then 6, then 7, and finally 8 into the expression -(n-5) 

doing this we'd end up with: 

-(2-5) = 3 
-(3-5) = 2 
-(4-5) = 1 
-(5-5) = 0 
-(6-5) = -1 
-(7-5) = -2 
-(8-5) = -3 

so then, after we do all that, we add up all the values we found, in this case they all cancel each other out and go to zero: 

3 + 2 + 1 + 0 + (-1) + (-2) + (-3) = 0 

It might be a glitch in the system, but good job with all those points