The height (ft) of an object is launched into the air given by the function h(t)=-6t^2+120t+17 where t is the time in seconds. When will the obj reach its maximum height ?
What is the max height?
After how many seconds will it hit the ground?

Object will reach the max height in 10 seconds.

Max. height is 1817.

It will hit the ground in 20 seconds.

Step-by-step explanation:

In order to find the x value which makes the function take its greatest value, you need to take the derivative of the function and equalize the result to 0.

h'(t)=-12t+120=0

t=10

The object will reach its maximum height in 10 seconds.

h(10) (maximum height) = 6.10.10+120.10+17= 600+1200+17=1817

Considering this is a parabola, time in total is two times more than the time passed until reaching the max. height.

10.2=20

4th option is correct xy=-10

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