The perimeter of a playing field for a certain sport is 174 ft. The field is a rectangle, and the length is 45 ft longer than the width Find the dimensions. The width of the playing field is 20 ft.
(Type an integer or a decimal.)​

21 ft by 66 ft

Step-by-step explanation:

From the question,

P = 2(L+W) Equation 1

Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.

If the Length of the Field is 45 ft longer than the width,

L = 45+W Equation 2

Substitute Equation 2 into equation 1

P = 2(45+W+W)

P = 90+4W Equation 3

Given: P = 174 ft.

Substitute into equation 3

174 = 90+4W

4W = 174-90

4W = 84

W = 84/4

W = 21 ft.

Substituting the value of W into equation 2

L = 45+21

L = 66 ft.

Hence the dimensions of the playing field is 21 ft by 66 ft

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step-by-step explanation:

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