I NEED HELP ASAP A football quarterback goes for a two-point conversion when the ball is within 10 yards of the end zone. During the game, he has two opportunities for a two-point conversion. He misses the first attempt 50% of the time. When he misses the first attempt, he misses the second attempt 15% of the time. What is the probability of missing both two-point conversion attempts?

P = 0.075     P = 7.5%

Step-by-step explanation:

We pretty much look for the probability that the player fails the first attempt and also fails the second attempt.

We know for a fact that the probability that the quarterback fails the first attempt is:

p(1) = 0.5

and we know that the probability that the quarterback fails the second attempt after failing the first is:

p(2/1) = 0.15  

Then the probability of failure of both attempts is:

P(2/1) = p(1 and 2) / p(1)

p(1 and 2) = P(1) * P(1/2)

p(1 and 2) = 0.5 * 0.15

and that is

p(1 and 2) = 0.075

you probably didn't want the nerdy stuff but oh well

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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