If you think of the equation as an equation for a line. =+
y
=
m
x
+
b

where

=5/9(−32)
C
=
5
/
9
(
F
−
32
)

or

=5/9−5/9(32)
C
=
5
/
9
F
−
5
/
9
(
32
)

you can see the slope of the graph is 5/9
5
/
9
, which means that for an increase of 1 degree Fahrenheit, the increase is 5/9
5
/
9
of 1 degree Celsius. Therefore, statement I is true.

This is the equivalent to saying that an increase of 1 degree Celsius is equal to an increase of 9/5
9
/
5
degrees Fahrenheit. Since 95
9
5
= 1.8, statement II is true.

On the other hand, statement III is not true, since a temperature increase of 9/5
9
/
5
degrees Fahrenheit, not 5/9
5
/
9
degree Fahrenheit, is equal to a temperature increase of 1 degree Celsius.

The final answer is D.

Which is the scale factor proportion for the enlargement shown?

Use a standard normal table to determine the probability. give your answer as a decimal to four decimal places. −1.5< < 1.5)

Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. here are data on the "penetrability" of the same type of soil at two levels of compression. penetrability is a measure of how much resistance plant roots will meet when they try to grow through the soil. compressed soil 2.85 2.66 3 2.82 2.76 2.81 2.78 3.08 2.94 2.86 3.08 2.82 2.78 2.98 3.00 2.78 2.96 2.90 3.18 3.16 intermediate soil 3.17 3.37 3.1 3.40 3.38 3.14 3.18 3.26 2.96 3.02 3.54 3.36 3.18 3.12 3.86 2.92 3.46 3.44 3.62 4.26 use the data, omitting the high outlier, to give a 95% confidence interval for the decrease in penetrability of compressed soil relative to intermediate soil. compute degrees of freedom using the conservative method. interval: to