Use trigonometric substitution to verify that

∫0xa2−t2√dt
〖√(a^2-t^2 ) dt〗=1/2 a^2 sin^(-1)⁡〖x/a〗+1/2 x√(a^2-x^2 )

use the figure to give trigonometric interpretations of both terms on the right side of the equation in part (a).

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.