Triangle ABC is graphed on a coordinate plane with vertices at A (-3,7), B (9,-8), and C(-5,-6). If triangle ABC is dilated by a scale factor of m with the origin as the center of dilation to create triangle A'B'C', what will be the coordinates of the dilated vertex B? (9+m, -8m) (9m, 8m) (9+m, 8+m) (9m, -8m) ​

i really dont know

step-by-step explanation:

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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