What is the perimeter of the rectangle whose vertices are at (6, 3), (−6, 3), (−6, −1), and (6, −1)?

Given:

The vertices of a rectangle are (6, 3), (−6, 3), (−6, −1), and (6, −1).

To find:

The perimeter of the rectangle.

Solution:

Distance formula:

Let the vertices of a rectangle are A(6, 3), B(−6, 3), C(−6, −1), and D(6, −1).

Using the distance formula, we get

Similarly,

Now, the perimeter of the rectangle is:

Therefore, the perimeter of the rectangle is 32 units.

step-by-step explanation:

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step-by-step explanation:

f(gx)=f(1/x+2)

=(1/x+2)+2

=(1+2x)/2+2

=(1+2x+4)/2

= (2x+5)/2