Please please help please please ASAP please please help

r = 3 cm , LA= 30π cm^2 , SA = 48π cm^2

Step-by-step explanation:

This is a bit more difficult because we have to use the inverse formula

if

V = base area x height

we can obtain

base area = V/height

base area = 45π/5 = 9π cm^2

If

base area = radius^2 π

we can obtain

radius = √base area / π

r = √9 x π/π = 3 cm

base perimeter = 3 x 2 x π = 6π cm

LA = 6π x 5 = 30π cm^2

SA = 9π x 2 + 30 π = 48π cm^2

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

(a) the volume of the cone is 20/3 in3

hence, option a is correct.