The height y, in feet, of a football x seconds after it is thrown is modeled by the equation y = –16x2 + 24x + 1. What information does the zero of the equation 6 = –16x2 + 24x + 1 represent? - the height of the ball after 6 seconds
- when the ball is 6 ft above the ground
- the initial upward velocity of the ball
- the horizontal distance traveled by the ball when it is 6 ft above the ground

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

~just a girl in love with shawn mendes