Abigail invested $77,000 in an account paying an interest rate of 8\tfrac{3}{8}8 8
3
​
% compounded annually. Gavin invested $77,000 in an account paying an interest rate of 8\tfrac{1}{8}8
8
1
​
% compounded monthly. After 14 years, how much more money would Gavin have in his account than Abigail, to the nearest dollar?

7.3

step-by-step explanation:

answer:

at time x=0 we have 1000, at time x=1 we have 2000, at time x=2 we have 4000.  

so that's an initial value of 1000 and a ratio of 2,

y = 1000 (2^x)

hope this !

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.

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α. мσℓє¢υℓє σf ωαтєя

в.тнєє-¢αявσи ѕυgαя

¢. "єχ¢ιтє∂" єℓє¢тяσи

∂. иα∂ρн

му αиѕωєя: ιт ιѕ ¢. "єχ¢ιтє∂" єℓє¢тяσи

нσρє ι ¢συℓ∂ нєℓρ υ