A bag cohtains 4 red marbles, 5 blue marbles and 3 green marbles. If two marbles are drawn out of the bag, what is the exact probability that both marbles drawn will be blue?​

5/12

Step-by-step explanation:

total number of marble is 12 total number of blu is 5

12.5%

Step-by-step explanation:

you have 7 reds of 14 total.

the 1st marble has 7 of 14 probability of being red

the 2nd has 6 of 13 of being red

the 3rd has 5 of 12 of being red

multiplying this out you have:

(7/14)*(6/13)*(5/12)=210/2184

THAT will condense down to 5/52 or 9.615%

this does assume not placing the balls back in between draws

if you do put them back in between draws you would have 7 of 14 chance each draw

that would give you by multiplying out

(7/14)*(7/14)*(7/14)=343/2744

that condenses to 1 of 8 or 12.5%

ok

step-by-step explanation: