Ralph has a cylindrical container of parmesan cheese. The diameter of the base of the container is 2.75 inches, and the height is 6 inches. What is the area of a horizontal cross section of the cylinder to the nearest tenth of a square inch?

The solution is given below:

Step-by-step explanation:

The computation of the area of the horizontal cross section of the cyclinder is given below:

In the case when it is a circle

The area of the circle is

= πr^2

= 3.14 × (2.75 ÷ 2)^2

= 11.873 inches^2

In the case when it is a rectangle

The area of the rectangle is

= 6 × 2.75

= 16.5 inches^2

Hence, the above show the calculations

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a