Mathematics, 16.04.2021 21:30 clipsyden
An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is
s(t) = -4.9t^2 + 19.6t + 58.8, where s is in meters. How high will the object be after 2 seconds?
78.4 feet
117.6 feet
194. 04 feet
1.96 feet
Answers: 3
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An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation...
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