What is the sum of the geometric series in which a1 = 4, r = 3, and an = 324? Hint: cap s sub n equals start fraction a sub one left parenthesis one minus r to the power of n end power right parenthesis over one minus r end fraction comma r ≠ 1, where a1 is the first term and r is the common ratio. (4 points)

Sn = 1,535
Sn = −484
Sn = 971
Sn = 484

a

step-by-step explanation:

step-by-step explanation:

no solution.

step-by-step explanation:

because it just is

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10