Find the perimeter of a quadrilateral with vertices at C (2, 4), D (1, 1), E (5, 0), and F (3, 4). Round your answer to the nearest hundredth when necessary.

9514 1404 393

  12.76 units

Step-by-step explanation:

The distance formula is useful for finding the lengths of segments between given coordinates.

  d = √((x2 -x1)² +(y2 -y1)²)

Then the lengths of the line segments are ...

  CD = √((1-2)² +(1-4)²) = √10

  DE = √((5-1)² +(0-1)²) = √17

  EF = √((3-5)² +(4-0)²) = √20

  FC = √((2-3)² +(4-4)²) = 1

Then the perimeter is ...

  √10 +√17 +√20 +1 ≈ 12.7575 ≈ 12.76 units

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In the attached, the length of "polyline" CDEF is shown as 11.76. The segment FC is shown separately.

i dont know i just need points

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step-by-step explanation:

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