Determine the numerical value of x ​

x = 10

Step-by-step explanation:

OA = OD ( both radii of the circle )

OD = OB + BD = x + 16

OB is at right angles to OB ( line from centre to midpoint of chord is right )

Using Pythagoras' identity in right triangle ABO

OA² = OB² + AB² , that is

(x + 16)² = x² + 24²

x² + 32x + 256 = x² + 576 ( subtract x² from both sides )

32x + 256 = 576 ( subtract 256 from both sides )

32x = 320 ( divide both sides by 32 )

x = 10

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: