Two chords intersect within a circle to form an angle whose measure is 53 degrees. If the arcs are represented by 3x+3 and 10x-14, find the measure of the LARGER of these two arcs.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

hi how are you doing today, if you need just ask me.

step-by-step explanation:

step-by-step explanation: