Elsa took out a 2-year loan to buy a car at a 6% simple interest rate. If she has to pay $264 in interest; How much interest did she pay each 1 year?

How much principal did she borrow?

P = I / rt is the formula we're going to use.

P is the principle (which is what we're solving for)

I = the interest accrued over the specified amount of time (2 years)

r = the interest rate (6%)

t = the time specified (2 years)

Change the percent to a decimal. Place the decimal two places to the left to make 0.06.

P = 264 / 0.06(2)

P = 264 ÷ 0.12 = 2,200

Principal borrowed would be $2,200

As interest paid in 2 years is $264

Therefore,Interest paid in 1 year=$264/2=$132

As p×r×t/100=S I.

Therefore ,P=S.I/(r×t) ×100

P=264/(6×2)×100

P=264/12 ×100

P=22×100

P=$2200

4a. is 3 miles every hour

4b. is 1/3 of an hour per mile

step-by-step explanation:

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}