The sum of two consecutive numbers is 477. What are the numbers?

158 + 159 + 160 = 477

Step-by-step explanation:

Here we will use algebra to find three consecutive integers whose sum is 477. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 477. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 477

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 477

3X + 3 = 477

3X + 3 - 3 = 477 - 3

3X = 474

3X/3 = 474/3

X = 158

Which means that the first number is 158, the second number is 158 + 1 and the third number is 158 + 2. Therefore, three consecutive integers that add up to 477 are 158, 159, and 160.

158 + 159 + 160 = 477

I hope it will help u dear

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

i dont know

step-by-step explanation: