Zane and his favorite geometry student, , have just set sail for a day of fun on lake Erie. A spring squall quickly forms and catches you off guard, leaving you adrift on the lake. Zane suddenly discovers he has an irrational fear of water and is reduced to hugging the mast. You hear Sherman barking from the top of a lighthouse to help guide you to shore. In order to save Zane and yourself, you must calculate how far away you are from this lighthouse. Using a range finder, you expertly measure the distance from the sailboat to the top of the lighthouse at 350 yards. angle B is 40 degrees.

(a) Based on the above information, find the distance across the water from the sailboat to the island

where the lighthouse is standing. You can only use trigonometry to solve. You must show all work for

credit. Round your answer to the nearest whole number if needed.

(b)Calculate the height of the lighthouse. You can only use trigonometry or Pythagorean Theorem to

solve.

Water is the Adjacent of this right triangle. 350 yards is the length of the Hypotenuse. We have given angle B, 40 degrees.

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According to SOH CAH TOA, we use CAH (cosineΘ = adjacent/hypotenuse).

cosine40 = x/350

[multiply both sides by 350]

350 · cosine40 = x

[put calculator in degree mode]

x ≈ 268 yards

So, the distance across the water from sailboat to the island is 268 yards.

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Let's use pythagorean theorem since we already know the adjacent and hypotenuse to find the opposite (opposite is also known as height).

a^2 + b^2 = c^2

a^2 + (268)^2 = (350)^2

a^2 + 71824 = 122500

a^2 = 122500 - 71824

a^2 = 50676

[square both sides]

=

a =

a ≈ 225

So, the height, opposite, of the lighthouse is 225 yards.

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for any of you who need the translation here it is

step-by-step explanation:

find the angular size of the equatorial radius of the earth, if the horizontal parallax of the sun

linear

step-by-step explanation: