What is the equation of a line that contains the point (6,-4) and has a slope of 3/4? A. y-4 = 3/4 (x-6) B. y+ 4 = 3/4 (x-6) C. y- 6 = 3/4 (x-4) D. y-6 = 3/4 (x+4)

B. y+ 4 = 3/4 (x-6)

Step-by-step explanation:

Given:

m = 3/4

Slope-intercept:

y - y1 = m(x - x1)

y + 4 = 3/4(x - 6)

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point