Can someone give steps to the solution for this problem : Find the 6th term of the arithmetic sequence x-3x−3, -x-5−x−5, -3x-7, ...−3x−7,...

2x−1−7−x3x−3 2 x − 1 − 7 − x 3 x − 3. =2x−1−7−x3(x−1) = 2 x − 1 − 7 − x 3 ( x − 1 ). =2.3(x−1).3−7−x3(x−1) = 2.3 ( x − 1 ) .3 − 7 − x 3 ( x − 1 ).

Step-by-step explanation:

x 3x-1 = 5 (x-1) -2 (7-2x). 3x − 1 = 5 (x − 1) −2 (7−2x) 3 x - 1 = 5 (x - 1) - 2 (7 - 2 x). Since x x is on the right side of the equation, we swap it so it is on the left side of the equation

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