Start with a square of side length 1. Join the midpoints of its four sides to form a smaller square and 4 right triangles. Let A1 be the area of one of the right triangles. Now, join the midpoints of each side of the smaller square to form a new even smaller square and 4 new right triangles. Let A2 be the area of one of the new right triangles. Continue the process forever. Requried:
a. Find a formula for A.
b. Determine whether the sequence A converges. If it does converge, what is the limit?

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

b. ol

step-by-step explanation:

i got the answer right on edg.

congruent: (geometry) (of figures) identical in form; coinciding exactly when superimposed.