A traveling circus is moving in a train consisting of 20 cars, which were randomly adjoined to each other. 2 cars are carrying clowns, 2 cars house trapeze artists, 4 are reserved for lions, 4 - for bears, 4 - for elephants, and 4 for tents and provisions. What is the probability that no elephant or bear car precedes the first car with lions

the no elephant or bear car precedes the first car with lions is 0.60

Step-by-step explanation:

The computation of the probability is shown below:

= 1 - (no depend or acrobat car precedes)

=  1 - (4 ÷ 20  + 4 ÷ 20)

= 1 - 8 ÷ 20

= 20 - 8 ÷ 20

= 12 ÷ 20

= 0.60

Hence, the no elephant or bear car precedes the first car with lions is 0.60

The same would be considered and relevant too

what? ?

what type of question is thiss

step-by-step explanation:

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step-by-step explanation: