Please help Solve each equation with the quadratic formula.
6) 4v2 + 6v - 88 = 0

Step-by-step explanation:

The quadratic equation given to us is ,

→ 4v² + 6v - 88 = 0 .

So , wrt to standard form of a quadratic equation ax² + bx + c = 0 , the Zeroes are given by using the Quadratic formula as ,

⇒ x = -b ± √ ( b² - 4ac) / 2a

⇒ x = -6 ± √ [6² - 4 × 4 × (-88) ] / 2×4

⇒ x = -6 ± √ [ 36 + 1408 ] / 8

⇒ x = -6 ± √ 1444 / 8

⇒ x = -6 ± 38 / 8

⇒ x = -6 +38/ 8 , -6 -38 / 8

⇒ x = 32/8 , -44/8

⇒ x = 4 , -11/2

Here I took v as x . So we can replace it .